(s^2+3s+2)Y=(2s+12)/(s+2)

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Solution for (s^2+3s+2)Y=(2s+12)/(s+2) equation: 



(s^2+3s+2)=(2s+12)/(s+2)

We move all terms to the left:

(s^2+3s+2)-((2s+12)/(s+2))=0



Domain of the equation: (s+2))!=0

s∈R



We get rid of parentheses

s^2+3s-((2s+12)/(s+2))+2=0

We multiply all the terms by the denominator


s^2*(s+2))+3s*(s+2))-((2s+12)+2*(s+2))=0

We add all the numbers together, and all the variables

s^2*(s+2))+3s*(s+2))-((2s+12)+2*(s=0

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